Question

In my iPhone application I have a tableview with custom imageview and loading images from remote location using AsyncImageView class. It works nicely, but one issue is, if I scroll the table, cells will be dequeued and it again trying to get the images from server. So, the method for loading image from AsyncImageView class is calling again and again hence increases the memory allocation, and eventually the app crashes.

Here is my code:

- (UITableViewCell *) getCellContentView:(NSString *)cellIdentifier {

    CGRect CellFrame = CGRectMake(0, 0, 300, 40);

    CGRect userImageFrame = CGRectMake(5, 7, 36, 36);

    UIImageView *userImage;

    UITableViewCell *cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:cellIdentifier] autorelease];
    [cell setFrame:CellFrame];

    userImage = [[UIImageView alloc]init];
    userImage.frame = userImageFrame;
    userImage.tag = 3;
    [cell.contentView addSubview:userImage];
    [userImage release];

    return cell;
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *CellIdentifier = @"Cell";

    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];

    if(cell == nil)
        cell = [self getCellContentView:CellIdentifier];
    else
        [[AsyncImageLoader sharedLoader] cancelLoadingImagesForTarget:cell.imageView];

    UIImageView *userImage = (UIImageView *)[cell viewWithTag:3];

    cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator;
    cell.selectionStyle = UITableViewCellSelectionStyleGray;
    NSString *url = [[NSString alloc]initWithFormat:@"%@%@", CommonImageURL,[AllUsersProfileImageArray objectAtIndex:indexPath.row]];
    NSURL *imageUrl =  [NSURL URLWithString:[url stringByAppendingFormat:@"?%i", rand()]];
    [url release];

    userImage.image = [UIImage imageNamed:@"defaultPerson.png"];
    userImage.imageURL = imageUrl;
    return cell;
}

Is there any possible way to fix the issue? Please help.

Answer 1

The best solution will be caching the image that is already downloaded and displaying it from there.

You need to write code for that, or there are some libraries which provide such feature:

1. HJCache
2. SDWebImage