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Home/ Questions/Q 9196497
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Editorial Team
  • 0
Editorial Team
Asked: June 17, 20262026-06-17T21:51:46+00:00 2026-06-17T21:51:46+00:00

In my lSearch function (linear search), I am trying to pass by reference a

  • 0

In my lSearch function (linear search), I am trying to pass by reference a variable named *numComparisons.

Everytime a comparison is made it should increment but for some reason it is not doing this. Why not? When it goes to the end of main.. the function does work (as in it’ll find a comparison or it will return -1 if no comparison is found) but the numComparisons value outputs to 0 everytime.

int lSearch(int arr[], int size, int target, int *numComparisons)
{
    int counter;

    for(counter = 0; counter < size; counter++)
    {  
        *numComparisons++;

        if(arr[counter] == target)
           return(*numComparisons);
    }
    return(-1);
}


int main(int argc, char * argv[])
{
   int enterNumbers[1000], copy[1000], counter;
   int numComparisons = 0, target = 26;

   printf("Enter in numbers and press -999 when you are done: ");

   for(counter = 0;; counter++)
   {
      scanf("%d", &enterNumbers[counter]);

      if(enterNumbers[counter] == -999)
          break;  
   }

   arrayCopy(enterNumbers, copy, counter);
   sort(copy, counter);

   if(lSearch(copy, counter, target, &numComparisons) >=0)
   {
      printf("Target number found in linear search.\n");
      printf("Number of comparisons: %d\n", numComparisons);
   }
   else
   {
      printf("Target number was not found in the linear search\n");
      printf("Number of comparisons: %d\n", numComparisons);
   }
   return 0;
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T21:51:47+00:00Added an answer on June 17, 2026 at 9:51 pm

    Change

        *numComparisons++;
    

    to

        (*numComparisons)++;
    

    Postfix increment has higher precedence than the dereference operator, so your code increments the pointer instead of incrementing the pointed-to value.

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