Question

In my method that writes to a database, I handle errors as shown in the code below. In catch (DbUpdateException ex) I want to re-throw the exception and catch it in the last catch (Exception ex).

Is that possible and how to do that? Code below doesn’t do that.

        using (Entities context = new Entities())
        {
            try
            {
                context.Office.Add(office);
                retVal = context.SaveChanges();
            }
            catch (DbUpdateException ex)
            {
                SqlException innerException = ex.GetBaseException() as SqlException;
                if (innerException != null && innerException.Number == (int)SQLErrorCode.DUPLICATE_UNIQUE_CONSTRAINT)
                {
                    throw
                        new Exception("Error ocurred");
                }
                //This is momenty where exception is thrown.
                else
                {
                    throw ex;
                }
            }
            catch (Exception ex)
            {
                throw
                    new Exception("Error");
            }
        }

Answer 1

have you tried try nesting your try...catch blocks?

using (Entities context = new Entities())
    {
        try
        {
            try
            {
                context.Office.Add(office);
                retVal = context.SaveChanges();
            }
            catch (DbUpdateException ex)
            {
                SqlException innerException = ex.GetBaseException() as SqlException;
                if (innerException != null && innerException.Number == (int)SQLErrorCode.DUPLICATE_UNIQUE_CONSTRAINT)
                {
                    throw new Exception("Error ocurred");
                }
                //This is momenty where exception is thrown.
                else
                {
                    throw ex;
                }
            }
        }
        catch (Exception ex)
        {
            throw new Exception("Error");
        }
    }