Question

In my mode I am selecting a field as

$query1 = $this->db->query("SELECT dPassword 
                    FROM tbl_login
                    WHERE  dEmailID='[e-mail]'");

How to return dpassword as a variable to my controller
I tried this way return dpassword;

Answer 1

The following is also fine:

if($query1->num_rows() > 0){
    $row = $query1->row();
}
return $row->dPassword;

Then if your query was to return more than a single row you could operate on the results like so:

foreach($query1->result() as $row){
echo $row->field1;
echo $row->field2;
echo $row->etcetera;
}

For single row results i usually return the row directly from the model like so:

return $query1->row();

Here is an example of this:

function select_provider_details($provider_id)
    {
        $this->db->select('*');
        $this->db->from('providers');
        $this->db->where('provider_id', $provider_id);

    $query = $this->db->get();

    if($query->num_rows() > 0)
    {
        $result['success'] = TRUE;
        $result['query'] = $query->row();
    }
    else
    {
        $result['success'] = FALSE;
        $result['error'] = "Provider not found in database";
        $result['errorcode'] = "E003";
        $result['query'] = $query->row();
    }
        return $result;
}

Or for a query expected to return multiple results i return the entire results object:

return $query1;