Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8526017
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 11, 20262026-06-11T08:08:57+00:00 2026-06-11T08:08:57+00:00

In my place of work I see this style used extensively:- #include <iostream> using

  • 0

In my place of work I see this style used extensively:-

#include <iostream>

using namespace std;

class A
{
public:
   A(int& thing) : m_thing(thing) {}
   void printit() { cout << m_thing << endl; }

protected:
   const int& m_thing; //usually would be more complex object
};


int main(int argc, char* argv[])
{
   int myint = 5;
   A myA(myint);
   myA.printit();
   return 0;
}

Is there a name to describe this idiom? I am assuming it is to prevent the possibly large overhead of copying a big complex object?

Is this generally good practice? Are there any pitfalls to this approach?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-11T08:08:58+00:00Added an answer on June 11, 2026 at 8:08 am

    Is there a name to describe this idiom?

    In UML it is called aggregation. It differs from composition in that the member object is not owned by the referring class. In C++ you can implement aggregation in two different ways, through references or pointers.

    I am assuming it is to prevent the possibly large overhead of copying a big complex object?

    No, that would be a really bad reason to use this. The main reason for aggregation is that the contained object is not owned by the containing object and thus their lifetimes are not bound. In particular the referenced object lifetime must outlive the referring one. It might have been created much earlier and might live beyond the end of the lifetime of the container. Besides that, the state of the referenced object is not controlled by the class, but can change externally. If the reference is not const, then the class can change the state of an object that lives outside of it.

    Is this generally good practice? Are there any pitfalls to this approach?

    It is a design tool. In some cases it will be a good idea, in some it won’t. The most common pitfall is that the lifetime of the object holding the reference must never exceed the lifetime of the referenced object. If the enclosing object uses the reference after the referenced object was destroyed, you will have undefined behavior. In general it is better to prefer composition to aggregation, but if you need it, it is as good a tool as any other.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have string like: This.is.a.great.place.too.work. (or) This/is/a/great/place/too/work/ I want to see if this string
This code seems to work fine class Rule<T> { public <T>Rule(T t) { }
My place of work currently uses CVS. A git migration is planned but it
At the place I work at, we have a custom security/authentication mechanism for internal
At my place of work we have a legacy document management system that for
At my current place of work we have a set way of going about
I happen to come across a Java code at my work place. Here's the
I am a one-man shop at the place where I work, and when I
I'm currently researching a project for the place that I work in. We are
in django 1.1.1, Place.objects.in_bulk() does not work and Place.objects.in_bulk(range(1, 100)) works and returns a

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.