Question

In my program I have uint4 x variable.
I have to print its value to stdout.

How can I implement it using printf?

Thank you in advance

Note:uint4 x a structure of 4 unsigned integers

Answer 1

uint4 is no standard type and there’s no common definition. I know of projects where uint4 refers to any of these:

• a 32-bit unsigned integer type (1)
• a 4-bit unsigned integer type, realized as a bitfield (2)
• a structure of 4 unsigned integers (3)

You’d print them like this:

// case (1)
#include <inttypes.h>
typedef uint32_t uint4;
uint4 x = 42;
printf("x = %" PRIu32, x);

// case (2)
typedef struct { unsigned value : 4; } uint4;
uint4 x = { 7 };
printf("x = %u", x.value);

// case (3)
typedef struct { unsigned x, y, z, w; } uint4;
uint4 quad = { 1, 2, 3, 4 };
printf("x = %u, y = %u, z = %u, w = %u", quad.x, quad.y, quad.z, quad.w);