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Home/ Questions/Q 3404042
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T05:20:03+00:00 2026-05-18T05:20:03+00:00

In my project, legacy code generates xml which has following structure : <Output> <Template

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In my project, legacy code generates xml which has following structure :

<Output>
    <Template recordID=12>
        <Employer type="String">
            <Value>Google</Value>
            <Value>GigaSoft inc.</Value>
        </Employer>
        <Designation  type="String">
            <Value>Google</Value>
        </Designation>
        <Duration  type="String" />
    </Template>
</Output>

I want to deserialize this xml into object which has following properties (I am using C#):

public class EmployerInfo
{
    string[] _employerName;
    string[] _designation;
    string _duration;
}

I tried to deserialize above xml using following attributes around members (NOTE : I have simplified code. I know we should not make data members public. This code is just for experimental purpose)

[XmlElement("Template")]
public class EmployerInfo
{
    [XmlElement("Employer")]
    public string[] _employerName;

    [XmlElement("Designation")]
    public string[] _designation;

    [XmlElement("Duration")]
    public string _duration;
}

To deserialize, in main class I wrote :

XmlSerializer serial = new XmlSerializer(typeof(Output));
TextReader reader = new StreamReader(@"C:\sample_xml.xml");
EmployerInfo fooBar = (EmployerInfo)serial.Deserialize(reader);
reader.Close();

After executing above code, all the members in fooBar object are set to null (default values). I think this is because xml structure does not match with class structure.

I tried to automatically generate class using xsd command but it created seperate classes for each of the data member .

I tried to give element names like XmlElement(“Employer.Value”) , XmlElement(“Template.Employer.Value”) but this also didnt work.

Can anyone please suggest some way to fit this xml into a EmployerInfo class ?

Thanks in advance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T05:20:04+00:00Added an answer on May 18, 2026 at 5:20 am

    Try:

    using System.IO;
    using System.Xml.Serialization;
    [XmlType("Template")]
    public class EmployerInfo
    {
        [XmlArray("Employer"), XmlArrayItem("Value")]
        public string[] _employerName;
    
        [XmlArray("Designation"), XmlArrayItem("Value")]
        public string[] _designation;
    
        [XmlElement("Duration")]
        public string _duration;
    }
    public class Output
    {
        public EmployerInfo Template { get; set; }
    }
    static class Program
    {
        static void Main()
        {
            XmlSerializer serial = new XmlSerializer(typeof(Output));
            using (var reader = new StringReader(@"<Output>
        <Template recordID=""12"">
            <Employer type=""String"">
                <Value>Google</Value>
                <Value>GigaSoft inc.</Value>
            </Employer>
            <Designation  type=""String"">
                <Value>Google</Value>
            </Designation>
            <Duration  type=""String"" />
        </Template>
    </Output>"))
            {
                EmployerInfo fooBar = ((Output)serial.Deserialize(reader)).Template;
            }
        }
    }
    

    Note also tat the type returned from XmlSerializer(typeof(Output))‘s deserialize method is going to be a Output record.

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