Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7488195
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 29, 20262026-05-29T14:47:07+00:00 2026-05-29T14:47:07+00:00

In my query below, i am trying to join one result set to another

  • 0

In my query below, i am trying to join one result set to another using the customerNumber identifier. I want to find each customer’s amount ordered and the amount paid. The sql does not execute with no help from Navicat Client

SELECT DISTINCT tabl1.customerNumber, 
                tabl1.amountOrdered, tabl2.amountPaid
FROM
(
     SELECT Distinct c.customerNumber, o.orderNumber, 
             SUM(od.quantityOrdered * od.priceEach) amountOrdered
     FROM ClassicModels.Customers c
     INNER JOIN ClassicModels.Orders o 
                ON c.customerNumber = o.customerNumber
     INNER JOIN ClassicModels.OrderDetails od 
                ON o.orderNumber = od.orderNumber
     GROUP BY od.orderNumber
     ORDER BY c.customerNumber
) tabl1
INNER JOIN 
(
     SELECT DISTINCT c.customerNumber, p.amount amountPaid
     FROM ClassicModels.Customers c 
     INNER JOIN ClassicModels.Payments p 
                ON c.customerNumber = p.customerNumber
 ) tabl2 ON tabl1.customerNumber = tabl2.customerNumber
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-29T14:47:11+00:00Added an answer on May 29, 2026 at 2:47 pm

    If you want to select each customer’s amount ordered and amount paid, this much simpler query should work:

    SELECT o.customerNumber as customerNumber, 
        SUM(od.quantityOrdered * od.priceEach) as amountOrdered, 
        SUM(p.amount) as amountPaid
    FROM ClassicModels.Orders o
    INNER JOIN ClassicModels.OrderDetails od
        ON o.OrderNumber = od.OrderNumber
    LEFT JOIN ClassicModels.Payments p
        ON p.customerNumber = o.customerNumber
    GROUP BY o.customerNumber
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

We have the query below. Using a LEFT OUTER join takes 9 seconds to
Ultimately I'm trying to transfer buffers from one machine to another. The code below
Description I'm trying to JOIN a table using the result of a stored function.
I have below query I am trying to show message 'No SubSource for this
I'm trying to convert the below SQL query to HQL and am having a
I am trying to get the below linq query to return -1 if there
I'm trying to mesh the below mysql query results into a single json object,
Why does the MySQL query below give error 1066 (Not unique table/alias: 'customer') ?
I've got a query below. I want to add a condition that if the
Trying to get two different counts in one query. To do this I am

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.