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Home/ Questions/Q 8150057
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T14:58:30+00:00 2026-06-06T14:58:30+00:00

In my REST WCF service I log all exceptions on WCF stack level (

  • 0

In my REST WCF service I log all exceptions on WCF stack level (IErrorHandler)

Here is my code:

public void PostPositions(List<Position> positions)
{
    if (!this.ValidateRequest()) return;
    foreach (var position in positions)
    {

I get exception:

Object reference not set to an instance of an object.

at Web.Services.MobileService.PostPositions(List`1 positions)
in
C:\CodeWorkspace\ClientServerCode\Web.Services\Rest\MobileService.cs:line
1170 at SyncInvokePostPositions(Object , Object[] , Object[] )
at System.ServiceModel.Dispatcher.SyncMethodInvoker.Invoke(Object
instance, Object[] inputs, Object[]& outputs)

Line 1170 in my code is for if (!this.ValidateRequest()) return;

What does it mean? There is no static methods, I work with instance of a class and this definitely exists. If exception happens inside ValidateRequest() I expect stack trace to show that.

Any pointers?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T14:58:31+00:00Added an answer on June 6, 2026 at 2:58 pm

    I would be willing to bet that positions is what’s null and that foreach(var position in positions) is what’s throwing the exception when calling GetEnumerator() on positions.

    if(positions != null)
    {
        foreach(var position in positions)
        {
            ...
        }
    }
    

    As you might guess, it’d be very easy for the line number calculation to get a bit jumbled here, since the foreach loop is just syntactic sugar for something like this:

    IEnumerator<Position> enumerator = positions.GetEnumerator();
    
    try
    {
        Position position;
    
        while(enumerator.MoveNext())
        {
            position = enumerator.Current;
    
            //The code from the body of your foreach loop goes here
        }
     }
     finally
     {
         //Clean up the enumerator
     }
    
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