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Home/ Questions/Q 3756220
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T09:49:06+00:00 2026-05-19T09:49:06+00:00

In my script, I have the following lines: $test = @imagecreatefrompng($name); if ($test) {

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In my script, I have the following lines:

$test = @imagecreatefrompng($name);
if ($test) { ... }

I am certain that $name represents an existing file on the disk, but I must handle cases where that file is not a valid PNG file (either because of a transfer error or because of a malicious user). I wish to handle such cases by not doing anything at all.

However, given the above code, my PHP interpreter stops on the first line with the following error message:

imagecreatefrompng() [function.imagecreatefrompng]: ‘foobar.png’ is not a valid PNG file

Shouldn’t ‘@‘ have suppressed this error message and had the function return falseas described in the documentation? How can I tell PHP that I know an error might happen and not interrupt the execution?

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  1. Editorial Team
    Editorial Team
    2026-05-19T09:49:07+00:00Added an answer on May 19, 2026 at 9:49 am

    You could use mime_content_type on the file.

    $image = 'file.png';
    if(is_file($image) && mime_content_type($image_type) == 'image/png'){
        // Image is PNG
    }else{
        // Not PNG
    }
    

    This will ensure the image is a file and a PNG.

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