Question

In my source code, it has the following for example:

menu = add_menu_item ((char **)HW_KIND, 21);
.
.
if(get_idx_by_str ((char **)HW_KIND, prev->column_section, 21, 0) < get_idx_by_str ((char **)HW_KIND, curr->column_section, 21, 0))
.
.
fprintf(fp, "# %d floor\n%d@%d\n\n", i, get_idx_by_str ((char **)HW_KIND, section->column_section, 21, 0), stop->stop_landing);
.
.
add_text_to_gtk_text_buffer (text_buffer, iter, NULL, -99, -99, "??????????Ե -- %s\n", HW_KIND[steel_col_data.sec_idx]);

I wanted to find all the sentences having exactly key HW_KIND then also 21 and then change 21 to 20. For example, the first three sentences above match the searching condition but the last one above doesn’t.

If in a terminal in Linux, grep "\<HW_KIND\>" foo.c | grep 21 will find all occurrences. How to define the substitute command in Vi editor?

Thank you.

Answer 1

You can use the following regex:

:%s/\(.\{-}HW_KIND.\{-}\)21\(.\{-}\)/\120\2/gc

With c option, you can confirm each replacement.
Try the above regex and watch it replaces the text as you want.
It will replace 4 matches.

\( and \) for capturing group, and \{-} for non-greeding match.