Question

In my string I have utf-8 non-breaking space (0xc2a0) and I want to replace it with something else.

When I use

$str=preg_replace('~\xc2\xa0~', 'X', $str);

it works OK.

But when I use

$str=preg_replace('~\x{C2A0}~siu', 'W', $str);

non-breaking space is not found (and replaced).

Why? What is wrong with second regexp?

The format \x{C2A0} is correct, also I used u flag.

Answer 1

Actually the documentation about escape sequences in PHP is wrong. When you use \xc2\xa0 syntax, it searches for UTF-8 character. But with \x{c2a0} syntax, it tries to convert the Unicode sequence to UTF-8 encoded character.

A non breaking space is U+00A0 (Unicode) but encoded as C2A0 in UTF-8. So if you try with the pattern ~\x{00a0}~siu, it will work as expected.