Question

In my template, I am looping through a list, trying to make a two-column layout. Because of the desired two-column layout, the markup I need to write in the for loop is dependent on whether forloop.counter0 is even or odd. If I had the full power of Python in the template language, determining the parity of forloop.counter0 would be trivial, but unfortunately that is not the case. How can I test whether forloop.counter0 is even or odd using the Django template language, or just as good, is there another way I could get elements in the list to display alternatively in the left and right columns?

Thanks in advance!

Answer 1

You can use the divisibleby filter with forloop.counter:

{% if forloop.counter|divisibleby:"2" %}even{% else %}odd{% endif %}