Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6586461
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T16:47:37+00:00 2026-05-25T16:47:37+00:00

In MyApp.something.BigObject I have a memory expensive object and I like to do this

  • 0

In MyApp.something.BigObject I have a memory expensive object and I like to do this var theObject = MyApp.something.BigObject;. My question is would that take up double the memory or not?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T16:47:37+00:00Added an answer on May 25, 2026 at 4:47 pm

    The “equals sign” is the assignment operator. If the RHS is an object, then a reference is assigned to the LHS, it does not clone or copy the object.

    So given:

    var obj = {};
    var b = obj;
    

    both obj and b reference the same object.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have an app that displays transcripts, something like this myapp.com/transcript/1234 The transcripts are
I think I'm missing something here. I have a directory like this: myapp |-lib
I am doing something like this in myproject.myapp.urls : from django.conf.urls.defaults import * urlpatterns
I have some code like this: EventLog.CreateEventSource(myApp, myAppLog); EventLog.WriteEntry(myApp, Test log message, EventLogEntryType.Error); Now,
I'm doing something like: {% extends 'base.html' %} {% url myapp.views.dashboard object as object_url
how I can create something like this: Html.MyApp.ActionLink()? Thanks.
Is there anything particularly bad about doing something like this in Javascript: myapp.someObject =
I have a controller defined like this: Ext.define('MyApp.controller.TestController', { extend: 'Ext.app.Controller', config: { },
I have a class file something like myclass.py in project/myapp/myclass.py how can I use
I have GWT RPC service and i am doing something like this inside my

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.