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Home/ Questions/Q 7408623
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:56:54+00:00 2026-05-29T05:56:54+00:00

in node.js, is there any shortcut to export ALL functions in a given file?

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in node.js, is there any shortcut to export ALL functions in a given file? i want to do this for unit testing purposes, as my unit tests are in a separate file from my production code.

I know i can go through and export each function manually, as in:

exports.myFunction = myFunction;

But i’m wondering if there is a simpler/slicker way to do this.

(and yes, i realize for modularity reasons it isn’t always a good idea to export all functions, but for unit testing purposes you do want to see all the little functions so you can test them piece by piece.)

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:56:54+00:00Added an answer on May 29, 2026 at 5:56 am

    You could do something like this:

    // save this into a variable, so it can be used reliably in other contexts
    var self = this;
    
    // the scope of the file is the `exports` object, so `this === self === exports`
    self.fnName = function () { ... }
    
    // call it the same way
    self.fnName();
    

    Or this:

    // You can declare your exported functions here
    var file = module.exports = {
      fn1: function () {
        // do stuff...
      },
      fn2: function () {
        // do stuff...
      }
    }
    
    // and use them like this in the file as well
    file.fn1();
    

    Or this:

    // each function is declared like this. Have to watch for typeos, as we're typing fnName twice
    fnName = exports.fnName = function () { ... }
    
    // now you can use them as file-scoped functions, rather than as properties of an object
    fnName();
    
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