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Home/ Questions/Q 6862939
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T02:43:18+00:00 2026-05-27T02:43:18+00:00

In OCaml, it is very easy to access to a binary operator, such as

  • 0

In OCaml, it is very easy to access to a binary operator, such as “+”:

# (+);;

( + ) : int -> int -> int

And modify them as I wish:

# let (+) = (+.);;

( + ) : float -> float -> float

In the Pervasives documentation, it says that (~-) is the unary operator corresponding to (-), meaning that ~-5 returns - :int = -5.

It is easy to modify (~-) as well:

let (~-) = (~-.);;

(~-) : float -> float

Fortunately, OCaml allows the user to use (-) as an alias for (~-):

Suppose we have defined

foo : int -> int -> int

We can call

foo 1 (-1);;

which is way better than

foo 1 (~-1);;

Well, the problem is, when I change (~-) definition, it doesn’t affect the unary operator (-)…

let (~-) x = 5;;

~-2;;
- : int = 5

-2;;
- : int = -2

Any idea how to modify the unary (-) as well ?

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  1. Editorial Team
    Editorial Team
    2026-05-27T02:43:19+00:00Added an answer on May 27, 2026 at 2:43 am

    As you said, unary (-) is a shortcut for (~-). Actually, your change has affected unary (-); for example, you have many ways to use (-) as you want after overriding (~-):

    # - (2+0);;
    - : int = 0
    
    # let a = 2;;
    val a : int = 2
    # -a;;
    - : int = 0
    

    So it works when you pass an expression to (-). In case you call -2, it will be parsed as a value, not a function application. It makes sense to follow the normal convention of negative numbers.

    BTW, I don’t recommend you to use this way of overriding operators. Since you have change (-) for any datatype having that operator, it may lead to confusion and strange bugs.

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