Question

In order to check if an input field is empty or has any value, will the following both methods work in same way? Or is any of them better than other?

if ($options['url']) {
    ..
}

Or

if ( isset ($options['url']) &&  ($options['url']!="") ) {
    ..
}

Answer 1

Without checking with isset() you will get at least a notice message if $options is not an array or the index url does not exist. So isset() should be used.

You could also use

if (! empty($options['url'])) {
    ...
}

Empty() checks for any false value (like an empty string, undefined, etc…).