Question

In order to simplify my work I usually do this:

   for FILE in ./*.txt; 
   do ID=`echo ${FILE} | sed 's/^.*\///'`; 
   bin/Tool ${FILE} > ${ID}_output.txt; 
   done

Hence process loops over all *.txt files.

Now I have two file groups – my Tool uses two inputs (-a & -b). Is there any command to run Tool for every FILE_A over every FILE_B and name the output file as a combination of both them?

I imagine it should look like something like this:

  for  FILE_A in ./filesA/*.txt; 
  do for FILE_B in ./filesB/*.txt; 
  bin/Tool -a ${FILE_A} -b ${FILE_B} > output.txt; 
  done 

So the process would run number of *.txt in filesA over number of *.txt in filesB.
And also the naming issue which I even don’t know where to put in…

Hope it is clear what I am asking. Never had to do such task before and a command line would be really helpful.

Looking forward!

Answer 1

NEWNAME="${FILE_A##*/}_${FILE_B##*/}_output.txt"