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Home/ Questions/Q 945241
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T22:43:18+00:00 2026-05-15T22:43:18+00:00

In order to view changes or diffs between commits, i use the following from

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In order to view changes or diffs between commits, i use the following from the command line:

svn diff -r 3000:3025 > daychanges.diff

I want to modify the command so that it generates diffs between successive commits, concatenates them and outputs to file, something like

svn diff -r 3000:3001 > daychanges.diff
svn diff -r 3001:3002 >> daychanges.diff
svn diff -r 3002:3003 >> daychanges.diff
...
svn diff -r 3019:3020 >> daychanges.diff

how can i write such a script?

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  1. Editorial Team
    Editorial Team
    2026-05-15T22:43:19+00:00Added an answer on May 15, 2026 at 10:43 pm

    You can write for loops in bash:

    http://www.cyberciti.biz/tips/how-to-generating-print-range-sequence-of-numbers.html

    Given that, it shouldn’t be all that difficult to write a script that calls svn diff over a range of commits.

    In a single line command, that could be run from the CLI:

    for ((start=3000,finish=3001; finish<=3025; start++,finish++)); do svn diff -r $start:$finish; done > out.file
    

    or if you prefer, the shorter version,

    for ((i=3000; i<3025; i++)); do svn diff -r $i:$(($i + 1)); done > out.file
    

    In a multi-line script:

    #!/bin/bash
    $begin=$1
    $end=$2
    $outfile=$3
    
    for ((start=$begin,finish=$begin+1; finish <= $end; start++,finish++))
    do
        svn diff -r $start:$finish
    done > $outfile
    

    (Omit the > $outfile if you just want to manually direct the output of the script.)

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