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Home/ Questions/Q 4551618
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T16:39:41+00:00 2026-05-21T16:39:41+00:00

In particular, I am implementing a QWizardPage (MyWizardPage) for a QWizard, and I want

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In particular, I am implementing a QWizardPage (“MyWizardPage”) for a QWizard, and I want to emit a signal (“sigLog”) from my override of the QWizardPage::nextId virtual method.

Like so:

class MyWizardPage
    : public QWizardPage
{
    Q_OBJECT
public:
    MyWizardPage();
    virtual int nextId() const;
Q_SIGNALS:
    void sigLog(QString text);
};

int MyWizardPage::nextId() const
{
    Q_EMIT sigLog("Something interesting happened");
}

But when I try this, I get the following compile error on the Q_EMIT line:

Error 1 error C2662: ‘MyWizardPage::sigLog’ : cannot convert ‘this’ pointer from ‘const MyWizardPage’ to ‘MyWizardPage &’

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T16:39:42+00:00Added an answer on May 21, 2026 at 4:39 pm

    It is possible to emit a signal from a const method by adding “const” to the signal declaration, like so:

    void sigLog(QString text) const;
    

    I tested this and it does compile and run, even though you don’t actually implement the signal as a normal method yourself (i.e. Qt is okay with it).

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