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Home/ Questions/Q 977453
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:54:24+00:00 2026-05-16T03:54:24+00:00

In Perl, the operator s/ is used to replace parts of a string. Now

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In Perl, the operator s/ is used to replace parts of a string. Now s/ will alter its parameter (the string) in place. I would however like to replace parts of a string befor printing it, as in

print "bla: ", replace("a","b",$myvar),"\n";

Is there such replace function in Perl, or some other way to do it? s/ will not work directly in this case, and I’d like to avoid using a helper variable. Is there some way to do this in-line?

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:54:24+00:00Added an answer on May 16, 2026 at 3:54 am
    require 5.013002; # or better:    use Syntax::Construct qw(/r);
    print "bla: ", $myvar =~ s/a/b/r, "\n";
    

    See perl5132delta:

    The substitution operator now supports a /r option that copies the input variable, carries out the substitution on the copy and returns the result. The original remains unmodified.

    my $old = 'cat';
    my $new = $old =~ s/cat/dog/r;
    # $old is 'cat' and $new is 'dog'
    
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