Question

In PHP 5.3 > can I type hint a object with interface?

Like so:

public function AddToFavorite(Trendmed\Interfaces\Favoriteable $entity) {}

or Im only limited to checking implementation inside function? I’ve tried to type hint like above and it’s not working.

Answer 1

From the manual:

PHP 5 introduces type hinting. Functions are now able to force
parameters to be objects (by specifying the name of the class in the
function prototype), interfaces, arrays (since PHP 5.1) or callable
(since PHP 5.4)

So it could use interfaces.