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Home/ Questions/Q 7590681
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Editorial Team
  • 0
Editorial Team
Asked: May 30, 20262026-05-30T20:27:56+00:00 2026-05-30T20:27:56+00:00

In PHP, it seems like every object can be converted to an integer, just

  • 0

In PHP, it seems like every object can be converted to an integer, just by calling intval($object), but this is not what I want. What I want is, to check if the object would be valid to be converted into an integer for what a human thinks it is.

I.e., valid objects would be

  • 12
  • 12.0
  • "12"
  • "12.0"

And not valid would be

  • MyFooInstance()
  • "some string"
  • "12.0.0"
  • "0 12.0"

etc.
In python, I could simply to the following:

try:
    int(var)
except (TypeError, ValueError):
    return False
return True

How can I achive this in PHP?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T20:27:57+00:00Added an answer on May 30, 2026 at 8:27 pm

    Use is_numeric.

    <?php
    $tests = array(
        "42", 
        1337, 
        "1e4", 
        "not numeric", 
        array(), 
        9.1
    );
    
    foreach ($tests as $element) {
        if (is_numeric($element)) {
            echo "'{$element}' is numeric", PHP_EOL;
        } else {
            echo "'{$element}' is NOT numeric", PHP_EOL;
        }
    }
    ?>
    
    
    '42' is numeric
    '1337' is numeric
    '1e4' is numeric
    'not numeric' is NOT numeric
    'Array' is NOT numeric
    '9.1' is numeric
    

    (From the page)

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