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Home/ Questions/Q 286647
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T05:39:18+00:00 2026-05-12T05:39:18+00:00

In Python 2.x when you want to mark a method as abstract, you can

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In Python 2.x when you want to mark a method as abstract, you can define it like so:

class Base:
    def foo(self):
        raise NotImplementedError("Subclasses should implement this!")

Then if you forget to override it, you get a nice reminder exception. Is there an equivalent way to mark a field as abstract? Or is stating it in the class docstring all you can do?

At first I thought I could set the field to NotImplemented, but when I looked up what it’s actually for (rich comparisons) it seemed abusive.

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  1. Editorial Team
    Editorial Team
    2026-05-12T05:39:19+00:00Added an answer on May 12, 2026 at 5:39 am

    Yes, you can. Use the @property decorator. For instance, if you have a field called “example” then can’t you do something like this:

    class Base(object):
    
        @property
        def example(self):
            raise NotImplementedError("Subclasses should implement this!")
    

    Running the following produces a NotImplementedError just like you want.

    b = Base()
    print b.example
    
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