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Home/ Questions/Q 7059865
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T04:17:00+00:00 2026-05-28T04:17:00+00:00

In python I have: nameh.append([area, hitratio]) nameh_sorted = sorted (nameh, key=lambda nameh: nameh[0]) I

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In python I have:

    nameh.append([area, hitratio])
    nameh_sorted = sorted (nameh, key=lambda nameh: nameh[0])

I sorted the [area, hitratio] based on the alphabet of the name of the area. Then I want to zip the sorted “hitratio” with another list “u” into [u1, hitratio1], [u2, hitratio2]…but I don’t know how to select the sorted hitratio in this case, the *nameh_sorted[1] is obviously wrong…

user = zip (u,*nameh_sorted[1])
user_sorted = sorted (user, key=lambda user: user[0])
x5, y5 = zip(*user_sorted) 

Can anyone help? Many thanks

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  1. Editorial Team
    Editorial Team
    2026-05-28T04:17:00+00:00Added an answer on May 28, 2026 at 4:17 am
    user = zip(u, (hitratio for area, hitratio in nameh_sorted))
    
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