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Home/ Questions/Q 886743
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T13:07:09+00:00 2026-05-15T13:07:09+00:00

In python, I know that looking up a locally scoped variable is significantly faster

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In python, I know that looking up a locally scoped variable is significantly faster than looking up a global scoped variable. So:

a = 4
def function()
    for x in range(10000):
        <do something with 'a'>

Is slower than

def function()
    a = 4
    for x in range(10000):
        <do something with 'a'>

So, when I look at a class definition, with an attribute and a method:

class Classy(object):
    def __init__(self, attribute1):
        self.attribute1 = attribute1
        self.attribute2 = 4
    def method(self):
        for x in range(10000):
            <do something with self.attribute1 and self.attribute2>

Is my use of self.attribute more like my first or second function? What about if I sub class Classy, and try to access attribute2 from a method in my sub class?

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  1. Editorial Team
    Editorial Team
    2026-05-15T13:07:10+00:00Added an answer on May 15, 2026 at 1:07 pm

    Locally scoped variables are fast because the interpreter doesn’t need to do a dictionary lookup. It knows at compile-time exactly how many local variables there will be and it creates instructions to access them as an array.

    Member attributes require a dictionary lookup, so they execute similar to your first example using globally scoped variables.

    For speed, you can do something like:

    attribute1 = self.attribute1
    # do stuff with attribute1
    

    which shadows attribute1 in a local variable, so only a single dictionary lookup is needed. I wouldn’t bother unless I’d done some profiling indicating that a method was a bottleneck, though.

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