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Home/ Questions/Q 7407391
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:42:43+00:00 2026-05-29T05:42:43+00:00

In python, is there an easy way to set up a file-like object for

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In python, is there an easy way to set up a file-like object for writing that is actually backed by multiple output streams? For instance, I want something like this:

file1 = open("file1.txt", "w")
file2 = open("file2.txt", "w")
ostream = OStreamWrapper(file1, file2, sys.stdout)

#Write to both files and stdout at once:
ostream.write("ECHO!")

So what I’m looking for is OStreamWrapper. I know it’d be pretty easy to write my own, but if there’s an existing one, I’d rather use that and not have to worry about finding and covering edge cases.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:42:44+00:00Added an answer on May 29, 2026 at 5:42 am

    Way to wrap all public file functions:

    import sys
    
    def _call_for_all_streams(func_name):
        def wrapper(self, *args, **kwargs):
            result = []
            for stream in self._streams:
                func = getattr(stream, func_name)
                result.append(func(*args, **kwargs))
            return result
        return wrapper
    
    class OStreamWrapper(object):
        def __init__(self, *streams):
            self._streams = streams
    
    for method in filter(lambda x: not x.startswith('_'), dir(file)):
        setattr(OStreamWrapper, method, _call_for_all_streams(method))
    
    if __name__ == '__main__':
        file1 = open("file1.txt", "w")
        file2 = open("file2.txt", "w")
        ostream = OStreamWrapper(file1, file2, sys.stdout)
        ostream.write("ECHO!")
        ostream.close()
    

    But it’s kinda dirty.

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