Question

In Python it’s possible to do something like this:

def blarg():
    return "blargidy", "blarg"

i, j = blargh()

Is there something similar available in scala?

Answer 1

You can return a tuple:

def blarg = ("blargidy", "blarg")

val (i, j) = blarg

Note the pattern-matching syntax for parallel variable assignment: this works for any pattern, not just for tuples. So for instance:

val list = 1 :: 2 :: 3 :: Nil

val x :: y = list // x = 1 and y = 2 :: 3 :: Nil