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Home/ Questions/Q 7932053
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T20:53:58+00:00 2026-06-03T20:53:58+00:00

In Python (tried this in 2.7 and below) it looks like a file created

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In Python (tried this in 2.7 and below) it looks like a file created using tempfile.NamedTemporaryFile doesn’t seem to obey the umask directive:

import os, tempfile
os.umask(022)
f1 = open ("goodfile", "w")
f2 = tempfile.NamedTemporaryFile(dir='.')
f2.name

Out[33]: '/Users/foo/tmp4zK9Fe'

ls -l
-rw-------  1 foo  foo  0 May 10 13:29 /Users/foo/tmp4zK9Fe
-rw-r--r--  1 foo  foo  0 May 10 13:28 /Users/foo/goodfile

Any idea why NamedTemporaryFile won’t pick up the umask? Is there any way to do this during file creation?

I can always workaround this with os.chmod(), but I was hoping for something that did the right thing during file creation.

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  1. Editorial Team
    Editorial Team
    2026-06-03T20:54:00+00:00Added an answer on June 3, 2026 at 8:54 pm

    This is a security feature. The NamedTemporaryFile is always created with mode 0600, hardcoded at tempfile.py, line 235, because it is private to your process until you open it up with chmod. There is no constructor argument to change this behavior.

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