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Home/ Questions/Q 784977
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:48:00+00:00 2026-05-14T20:48:00+00:00

In Scala, I can make a caseclass, case class Foo(x:Int) , and then put

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In Scala, I can make a caseclass, case class Foo(x:Int), and then put it in a list like so:

List(Foo(42))

Now, nothing strange here. The following is strange to me. The operator :: is a function on a list, right? With any function with one argument in Scala, I can call it with infix notation.
An example is 1 + 2 is a function (+) on the object Int. The class Foo I just defined does not have the :: operator, so how is the following possible?

Foo(40) :: List(Foo(2))

In Scala 2.8 RC1, I get the following output from the interactive prompt:

scala> case class Foo(x:Int)
defined class Foo

scala> Foo(40) :: List(Foo(2))
res2: List[Foo] = List(Foo(40), Foo(2))

I can go on and use it, but what is the explanation?

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  1. Editorial Team
    Editorial Team
    2026-05-14T20:48:01+00:00Added an answer on May 14, 2026 at 8:48 pm

    From the Spec:

    6.12.3 InfixOperations An infix operator can be an arbitrary
    identifier. Infix operators have
    precedence and associativity defined
    as follows.

    …

    The associativity of an operator is
    determined by the operator’s last
    character. Operators ending in a colon
    ‘:’ are right-associative. All other
    operators are left- associative.

    You can always see how these rules are applied in Scala by printing the program after it has been through the ‘typer’ phase of the compiler:

    scala -Xprint:typer -e "1 :: Nil"
    
    val r: List[Int] = {
      <synthetic> val x$1: Int = 1;
      immutable.this.Nil.::[Int](x$1)
    };
    
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