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Home/ Questions/Q 415087
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T18:20:47+00:00 2026-05-12T18:20:47+00:00

In scala it is possible to define a local block in a function. The

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In scala it is possible to define a local block in a function. The local block evaluates to the last statements, for example,

val x = {val x =1;x+1}

Here x==2, the inner val x is local to that block.

However those local blocks can cause sneaky bugs when writing anonymous classes. For example (from scala’s reference)

new Iterator[Int]
{...} // new anonymous class inheriting from Iterator[Int]

new Iterator[Int]

{...} //new Iterator[Int] followed by a "dangling" local block

Differntiating between the two cases is frustrating.
Sometimes those two code snippets can compile, for instance if instead of Iterator[Int], Range(0,1,1) is used.

I thought about it and couldn’t find a case where “dangling” local block (ie, a local block whose value isn’t use) is needed (or makes the code more elegant).

Is there a case where we want a local block, without using its value (and without putting it in a different function and calling this function)? I’ll be glad for an example.

If not, I think it would be nice to issue a warning (or even forbid altogther) whenever scalac encounter “dangling” local block. Am I missing something?

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  1. Editorial Team
    Editorial Team
    2026-05-12T18:20:48+00:00Added an answer on May 12, 2026 at 6:20 pm
      {
        import my.crazy.implicit.functions._
    
        // use them...
      }
    
      // code I know isn't touched by them.
    
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