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Home/ Questions/Q 8540089
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T11:31:12+00:00 2026-06-11T11:31:12+00:00

In Scala language, I want to write a function that yields odd numbers within

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In Scala language, I want to write a function that yields odd numbers within a given range. The function prints some log when iterating even numbers. The first version of the function is:

def getOdds(N: Int): Traversable[Int] = {
  val list = new mutable.MutableList[Int]
  for (n <- 0 until N) {
    if (n % 2 == 1) {
      list += n
    } else {
      println("skip even number " + n)
    }
  }
  return list
}

If I omit printing logs, the implementation become very simple:

def getOddsWithoutPrint(N: Int) =
  for (n <- 0 until N if (n % 2 == 1)) yield n

However, I don’t want to miss the logging part. How do I rewrite the first version more compactly? It would be great if it can be rewritten similar to this:

def IWantToDoSomethingSimilar(N: Int) =
  for (n <- 0 until N) if (n % 2 == 1) yield n else println("skip even number " + n)
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  1. Editorial Team
    Editorial Team
    2026-06-11T11:31:13+00:00Added an answer on June 11, 2026 at 11:31 am
    def IWantToDoSomethingSimilar(N: Int) = 
      for {
        n <- 0 until N
        if n % 2 != 0 || { println("skip even number " + n); false }
      } yield n
    

    Using filter instead of a for expression would be slightly simpler though.

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