Question

In screenshots and projects, projectId is the connector. I get the error below when I run the following sql code:

SQL Code:

SELECT * FROM screenshots s, projects p WHERE s.projectId == p.projectId ORDER BY s.idscreenshot DESC

Error:

A Database Error Occurred

Error Number: 1064

You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near ‘== p.projectId ORDER BY s.idscreenshot DESC’ at line 1

SELECT * FROM screenshots s, projects p WHERE s.projectId ==
p.projectId ORDER BY s.idscreenshot DESC

Filename:
C:\Workspace\htdocs\Jan-2012\nurbell\system\database\DB_driver.php

Line Number: 330

Does anybody know why this is happening?

Answer 1

It’s happening because the SQL equality operator is =, not ==.

It’s also highly recommended to use explicit JOIN syntax to associate tables, rather than the implicit join syntax you’re using. So, for example, instead of:

SELECT * 
FROM screenshots s, projects p 
WHERE s.projectId = p.projectId 
ORDER BY s.idscreenshot DESC

You should use this:

SELECT * 
FROM screenshots s
JOIN projects p ON s.projectId = p.projectId 
ORDER BY s.idscreenshot DESC