In shell scripting (bash) why does the conditional get satisfied
if [ 1 ]
then
echo should not enter
fi
#Output
should not enter
In shell scripting ( bash ) why does the conditional get satisfied if [
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In shell scripting (bash) why does the conditional get satisfied
if [ 1 ]
then
echo should not enter
fi
#Output
should not enter
The square brackets in bash are equivalent to calling
testwith the arguments within the brackets.man testsays thatand
, and 1 is not an empty string.
if [ 0 ],if [ false ]andif [ no ]have the same result, butif [ "" ]has not.