Question

In short, I have a function like the following:

function plus($x, $y){
   echo $x+$y;
}

I want to tell the function its parameters as array like the following:

$parms = array(20,10);
plus($parms);

But unfortunately, not work.
I’m tired by using another way as the following:

$parms = array(20,10);
$func_params = implode(',', $parms);
plus($func_params);

And also not work, and gives me Error message:
Warning: Missing argument 2 for plus(), called in.....

And now, I’m at a puzzled.
What can I do to work ?

Answer 1

There is a couple things you can do.
Firstly, to maintain your function definition you can use call_user_func_array(). I think this is ugly.

call_user_func_array('plus', $parms);

You can make your function more robust by taking a variable number of params:

function plus(){
  $args = func_get_args();
  return $args[0] + $args[1];
}

You can simply accept an array and add everything up:

function plus($args){
  return $args[0] + $args[1];
}

Or you could sum up all arguments:

function plus($args){
  return array_sum($args);
}

This is PHP, there are 10 ways to do everything.