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Home/ Questions/Q 3482028
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T10:30:44+00:00 2026-05-18T10:30:44+00:00

In some code I saw recently there was a structure defined like this: typedef

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In some code I saw recently there was a structure defined like this:

typedef struct tagMyStruct {
    int numberOne;
    int numberTwo;
} MYSTRUCT;

The way I understand this, tagMyStruct is the new data type and MYSTRUCT is a variable that is created right there.

At another place, this was used like this:

MYSTRUCT *pStruct = new MYSTRUCT;

and it compiled fine with Visual Studio 2010. How is that valid C++? I thought MYSTRUCT was a variable and not a type?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T10:30:45+00:00Added an answer on May 18, 2026 at 10:30 am

    No. tagMyStruct is the name of the struct. In C, unlike C++, you must explicitly use the struct keyword every time you use the struct type. For example

    tagMyStruct x; //error
    struct tagMyStruct x; //OK
    

    To avoid writing struct all the time, struct tagMyStruct is typedef‘d to MYSTRUCT. Now you can write

    MYSTRUCT x; //ok, same as struct tagMyStruct x;
    

    What you thought this was (a variable definition) would be without the typedef keyword, like this

    struct tagMyStruct {
        int numberOne;
        int numberTwo;
    } MYSTRUCT;
    

    BTW

    MYSTRUCT pStruct = new MYSTRUCT; //error cannot convert MYSTRUCT* to MYSTRUCT
    

    is not valid C or C++ anyway. Maybe you mean

    MYSTRUCT* pStruct = new MYSTRUCT; //valid C++ (invalid C - use malloc instead of new in C)
    

    hth

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