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Home/ Questions/Q 8189303
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T03:13:56+00:00 2026-06-07T03:13:56+00:00

In SQL Server 2008; I have a tree. I need to get all child

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In SQL Server 2008;

I have a tree. I need to get all child nodes of node n (see diagram) and all child nodes of these child nodes, etc until the leaf nodes which is fairly trivial. I also need to be able to say ‘Take node o, go up the tree until we reach m and because m is a child of node n set some property of node o to some property of node m. Node o could be 3 levels deep (as illustrated) or 45 levels deep, x levels deep.

This gets all children of a given node (or area)

    --Return all sub-area structure of an area:

      WITH temp_areas (ParentAreaID, AreaID, [Name], [Level]) AS
      (
            SELECT ParentAreaID, AreaID, [Name], 0
            FROM lib_areas WHERE AreaID = @AreaID
            UNION ALL
            SELECT B.ParentAreaID, B.AreaID, B.[Name], A.Level + 1
            FROM temp_areas AS A, lib_areas AS B
            WHERE A.AreaID = B.ParentAreaID
      )

INSERT INTO @files (id) SELECT fileid FROM lib_filesareasxref where areaid in (select  areaid from temp_areas)

while exists (select * from @files)
begin
select top 1
@ID = id
from
@files ORDER BY id DESC

delete from @files where id = @id

tree

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T03:13:57+00:00Added an answer on June 7, 2026 at 3:13 am

    This will track back from @node_o until it reaches @node_m or it reaches the top of the tree (if @node_m is not above @node_o).

      WITH
        parents
      AS
      (
        SELECT
          A.ParentAreaID, A.AreaID, A.[Name], 0
        FROM
          lib_areas  AS A
        WHERE
          A.AreaID = @node_o
    
        UNION ALL
    
        SELECT
          A.ParentAreaID, A.AreaID, A.[Name], B.Level + 1
        FROM
          lib_areas  AS A
        INNER JOIN
          parents    AS B
            ON A.AreaID = B.ParentAreaID
        WHERE
          B.AreaID <> @node_m
      )
      SELECT
        *
      FROM
        parents
    
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