Question

In SQL Server, I have a start time column on a table such as:

2011-09-18 08:06:36.000
2011-09-19 05:42:16.000
2011-09-20 08:02:26.000
2011-09-21 08:37:24.000
2011-09-22 08:22:20.000
2011-09-23 11:58:27.000
2011-09-24 09:00:48.000
2011-09-25 06:51:34.000
2011-09-26 06:09:05.000
2011-09-27 08:25:26.000
...

My question is, how can I get the average hour and minute? I want to know that what is the average start time for this job. (for example 07:22)

I tried something like this but didn’t work:

select CAST(AVG(CAST(DATEPART(HH, START_TIME)AS float)) AS datetime) FROM

Thanks.

Answer 1

declare @T table(StartTime datetime)

insert into @T values
('2011-09-18 08:06:36.000'),
('2011-09-19 05:42:16.000'),
('2011-09-20 08:02:26.000'),
('2011-09-21 08:37:24.000'),
('2011-09-22 08:22:20.000'),
('2011-09-23 11:58:27.000'),
('2011-09-24 09:00:48.000'),
('2011-09-25 06:51:34.000'),
('2011-09-26 06:09:05.000'),
('2011-09-27 08:25:26.000')

;with C(Sec) as
(
  select dateadd(second, avg(datediff(second, dateadd(day, datediff(day, 0, StartTime), 0), StartTime)), 0)
  from @T
)
select convert(char(5), dateadd(minute, case when datepart(second, C.Sec) >= 30 then 1 else 0 end, C.Sec), 108)
from C
-----
08:08