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Asked: 2026-06-06T14:41:37+00:00

In the below program,i am not getting values from printf . #include<stdio.h> int main()

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In the below program,i am not getting values from printf.

#include<stdio.h>

int main()
{
    struct book
    {
        char name;
    float price;
    int pages;
    };
    struct book b1,b2,b3;

    printf("enter names prices & no. of pages of 3 books\n");
    scanf("%c %f %d",&b1.name,&b1.price,&b1.pages);
    fflush(stdin);
    scanf("%c %f %d",&b2.name,&b2.price,&b2.pages);
    fflush(stdin);
    scanf("%c %f %d",&b3.name,&b3.price,&b3.pages);
    fflush(stdin);
    printf("and this is what you entered\n");
    printf("%c %f %d",&b1.name,&b1.price,&b1.pages);
    printf("%c %f %d",&b2.name,&b2.price,&b2.pages);
    printf("%c %f %d",&b3.name,&b3.price,&b3.pages);
    return 0;
}

and this output I am getting

enter names prices & no. of pages of 3 books
a 34.6 23
b 23.4 34
c 63.5 23

and this is what you entered

0.000000 0∞ 0.000000 0╪ 0.000000 0Press any key to continue . . .

Why isn’t the output matching the input?

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1 Answer

  1. Editorial Team
    printf("%c %f %d",&b1.name,&b1.price,&b1.pages);
printf("%c %f %d",&b2.name,&b2.price,&b2.pages);
printf("%c %f %d",&b3.name,&b3.price,&b3.pages);

    Too much copy and paste methinks. You are passing pointers when printf expects chars, same for the floats and ints.

    You passed the address of those variables to scanf so that the function could change their value. When you use %d, %f, and %c printf expects an int (not a pointer to int), a float (not a pointer to float), and a char (not a pointer to char).

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