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Editorial Team
Asked: June 7, 20262026-06-07T12:11:04+00:00 2026-06-07T12:11:04+00:00

In The C++ Programming Language book, in list of operations (article 6.2) , Bjarne

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In “The C++ Programming Language” book, in list of operations (article 6.2), Bjarne Stoustrup wrote this:

create (place) new ( expr-list ) type

create (place and initialize) new ( expr-list ) type ( expr-list )

I’ve never heard about this kind of the new operator, and I’m interested what does it do.

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  1. Editorial Team
    Editorial Team
    2026-06-07T12:11:06+00:00Added an answer on June 7, 2026 at 12:11 pm

    This is called placement-new. You can create an object over already existing memory.

    Here’s an explanation and an useful question in SO

    You can also have nothrow, for example:

    char* pzNewBuffer = new (nothrow) char [2048];
    

    which tells, that new will not throw std::bad_alloc in case of out of memory, but it will return NULL, instead.


    Another example, that comes to my mind – the standard containers (probably) use placement new: when you call reserve, memory is allocated, but nothing is constructed/initialzed on this memory. So, when you insert (with std::vector<T>::push_back for example), if there’s allocated, but not initialized memory – placement new is used.

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