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Home/ Questions/Q 5968589
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T20:06:41+00:00 2026-05-22T20:06:41+00:00

In the code below, I have a dictionary of NSNumbers that are turned into

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In the code below, I have a dictionary of NSNumbers that are turned into an Array. It is then randomly sorted and the first four rows need to be displayed in the appropriate labels. NSLog does show that the array displays the appropriate numbers. I believe the code fails because I need to convert the NSNumbers into NSStrings. What is the applicable code or what am I overlooking?

-(IBAction)shakeit {
NSDictionary * myExampleDict = [[NSUserDefaults standardUserDefaults] dictionaryForKey:@"dictionaryKey"];
exampleArray = [myExampleDict allValues];
NSUInteger count = [exampleArray count];
for (NSUInteger i = 0; i < count; ++i) {
   int nElements = count - i;
   int n = (arc4random() % nElements) + i;
   [exampleArray exchangeObjectAtIndex:i withObjectAtIndex:n];
}
NSString *one = [exampleArray objectAtIndex:1];
NSString *two = [exampleArray objectAtIndex:2];
NSString *three = [exampleArray objectAtIndex:3];
NSString *four = [exampleArray objectAtIndex:4];
select1.text = one;
select2.text = two;
select3.text = three;
select4.text = four;
}
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  1. Editorial Team
    Editorial Team
    2026-05-22T20:06:42+00:00Added an answer on May 22, 2026 at 8:06 pm

    I believe the code fails because I
    need to convert the NSNumbers into
    NSStrings.

    you are right, try the following:

    NSString *one   = [[exampleArray objectAtIndex:1] stringValue];
    NSString *two   = [[exampleArray objectAtIndex:2] stringValue];
    NSString *three = [[exampleArray objectAtIndex:3] stringValue];
    NSString *four  = [[exampleArray objectAtIndex:4] stringValue];
    
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