In the code below, I would like to call the class method done of the class that includes the module from inside self.hello
Explanation:
A::bonjour will call Mod::hello so will B::ciao
I would like to be able to detect the “calling class” (A or B) in Mod::hello in order to be able to call the A::done or B::done
module Mod
def self.hello
puts "saying hello..."
end
end
class A
include Mod
def self.bonjour
Mod::hello
end
def self.done
puts "fini"
end
end
class B
include Mod
def self.ciao
Mod::hello
end
def self.done
puts "finitto"
end
end
While (perhaps) not as clean as Niklas’ answer, it’s still easily doable, and IMO cleaner than the usage pattern shown in the OP which relies on knowing which module is mixed in.
(I prefer not having to pass an argument to mixin methods like this when other means exist.)
The output:
The guts:
The modified class declarations, removing the explicit module reference:
You may also supply a default implementation of
done:As a comment to this post points out, if the snippet in the OP is a faithful representation of the actual usecase, you might as well use
extend(instead ofinclude), leaving everything cleaner:And the classes using
extend: