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Home/ Questions/Q 7248531
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T22:09:02+00:00 2026-05-28T22:09:02+00:00

In the code below, which case (1 or 2) is more efficient? static final

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In the code below, which case (1 or 2) is more “efficient”?

static final String NEWLINE = System.getProperty("line.separator");
Vector<String> text_vec = ...;
FileWriter file_writer = new FileWriter(path);
BufferedWriter buffered_writer = new BufferedWriter(file_writer);
try {
    for (String text: text_vec) {

        // Case 1: String concatenation
        buffered_writer.write(text + NEWLINE);

        // Case 2: Extra call to write()
        buffered_writer.write(text);
        buffered_writer.write(NEWLINE);
    }
}
finally {
    buffered_writer.close();
}

In case #1, as I understand, the String concatenation is handled by the Java compiler by automatically allocating a StringBuilder object. Since the String values are not known at compile time, it is not possible to concatenate “early” (during compile time).

So the question stands: Which one is more efficient (CPU/memory/wall clock time)?

I am leaving the exact definition of “efficient” to those whom answer. I am not an expert on the Java virtual machine.

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  1. Editorial Team
    Editorial Team
    2026-05-28T22:09:03+00:00Added an answer on May 28, 2026 at 10:09 pm

    Unless you benchmark it and prove that you have a good reason not to, you should write directly to the buffer. It’s there to provide an efficient method for writing to a file.

    Also, don’t forget to flush the buffer when you’re done writing to it.

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