In the code,
const int x = 3;
int y = 0;
y += x;
Is there any need to remove the const from x before doing the addition or is this maybe done implicitly in the addition operator definition?
In the code, const int x = 3; int y = 0; y +=
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In the code,
const int x = 3;
int y = 0;
y += x;
Is there any need to remove the const from x before doing the addition or is this maybe done implicitly in the addition operator definition?
Firstly, the
+=operator is an assignment operator (compound assignment). Its behavior though is equivalent toy = y + xcombination (exceptyis evaluated only once).Secondly, when used as an operand of addition operator (including the RHS of
+=as in your example)xparticipates in the expression as an rvalue, i.e. it is implicitly subjected to so called lvalue-to-rvalue conversion. This conversion immediately discardsconst, since rvalues of non-class types (intin your case) cannot be cv-qualified.