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Editorial Team
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Asked: 2026-05-15T22:07:10+00:00

In the examples, they create Intent as: Intent intent = new Intent(this, AlarmReceiver.class); But

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In the examples, they create Intent as:

Intent intent = new Intent(this, AlarmReceiver.class);

But suppose my AlarmReceiver class is in another app, how do I create this intent?

I’ve tried with

new Intent("com.app.AlarmReceiver")

but nothing happens.. It was not called..

Any idea?

—Broadcast definition added using the manifest editor on Eclipse:

<receiver android:name="AlarmReceiver"></receiver>
</application>

—
Related:
How do I start my app from my other app? (but this same code is not working for broadcasts..)

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1 Answer

  1. Editorial Team

    But my suppose my AlarmReceiver class
    is in another app, how do I create
    this intent?

    If you wrote the other app, add an <intent-filter> with a custom action string to the other app’s <receiver> element, then use an Intent with that action string.

    If you did not write the other app, ask whoever wrote it what the Intent should look like.

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