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In the expression a + b, is a guaranteed to be evaluated before b, or is the order of evaluation unspecified? I think it is the latter, but I struggle to find a definite answer in the standard.
Since I don’t know whether C handles this different from C++, or if evaluation order rules were simplified in C++11, I’m gonna tag the question as all three.
In C++, for user-defined types
a + bis a function call, and the standard says:For normal operators, the standard says:
These haven’t been changed for C++11. However, the wording changes in the second one to say that the order is “unsequenced” rather than unspecified, but it is essentially the same.
I don’t have a copy of the C standard, but I imagine that it is the same there as well.