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Home/ Questions/Q 9156011
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T12:41:43+00:00 2026-06-17T12:41:43+00:00

In the F# code I’m trying to convert to OCaml, I’ve run into the

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In the F# code I’m trying to convert to OCaml, I’ve run into the following:

    let rec parseList lst off =
        seq {
            if List.isEmpty lst then ()
            else
                match parse off <| List.head lst with
                | (Unmatched, _) as y -> yield y
                | (y, z) -> yield (y, z)
                            yield! parseList (List.tail lst) z
        }

I’m wondering about how to convert that seq{…} expression with yield‘s to OCaml? My first guess is that the seq would have to become a list.

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  1. Editorial Team
    Editorial Team
    2026-06-17T12:41:43+00:00Added an answer on June 17, 2026 at 12:41 pm

    Simplest translation (not tail recursive) is:

    let rec parseList lst off =
      match lst with
      | [] -> []
      | x::xs ->
          match parse off x with
          | Unmatched, _ as y -> [y]
          | y, z -> (y, z)::parseList xs z
    

    Tail recursive version is:

    let parseList lst off =
      let rec loop xs off = function
        | [] -> xs
        | y::ys ->
            match parse off y with
            | Unmatched, _ as x -> x::xs
            | _, z as x -> loop (x::xs) z ys in
      List.rev (loop [] off lst)
    

    Note that the F# code you’re starting from leaves a lot to be desired. The calls to List.head and List.tail are unnecessary potential sources of exceptions when you can more easily use pattern matching instead. And there are superfluous parentheses.

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