Question

In the following code I am converting a binary to decimal and then printing the character corresponding to it.

void convertToChar(int binaryChar[],int length)
{
int multiplier = 0;
int i;
int sum = 0;
for(i=length;i>=0;i++)
{
    sum = sum + (binaryChar[i]*pow(2,multiplier));
    multiplier = multiplier + 1;
}
printf("\nThe character is: %c",sum);
}

The problem is in the line sum = sum + (binaryChar[i]*pow(2,multiplier)); .It throws the error: warning: converting toint’ from double'.Please help!

Answer 1

Why are you using pow to calculate a power of 2? It’s too slow. Use 1 << p to get the p-th power of two. E.g., 1 << 0 will give 1, 1 << 1 will give 2, 1 << 2 will give 4. This is due to the nature of the bit shift operation: shifting one bit to the left is equivalent of multiplying by 2.

Also, it looks like you have an endless cycle in your program:

for(i=length;i>=0;i++)

If length is >= 0, the loop will never terminate.

This should fix it:

for(i = length - 1; i>=0; i--) sum += (binaryChar[i]*(1 << multiplier++));