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Home/ Questions/Q 6206219
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T05:24:49+00:00 2026-05-24T05:24:49+00:00

In the following code: public class SomeClass { // … constructor and other stuff

  • 0

In the following code:

public class SomeClass
{
    // ... constructor and other stuff

    public in SomeProperty
    {
        get
        {
            return SomeHeavyCalculation();
        }
    } 
}

I consider the class to be immutable, so every time SomeProperty is accessed, same value should be returned. My question is whether it is possible to avoid calculating the value each time. Is there some built in mechanism for caching such stuff?

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  1. Editorial Team
    Editorial Team
    2026-05-24T05:24:50+00:00Added an answer on May 24, 2026 at 5:24 am

    Yup – Lazy<T>, assuming you’re using .NET 4:

    public class SomeClass
    {
        private readonly Lazy<Foo> foo = new Lazy<Foo>(SomeHeayCalculation);
        // ... constructor and other stuff
    
        public Foo SomeProperty
        {
            get
            {
                return foo.Value;
            }
        } 
    }
    

    I assume you’re trying to avoid performing the calculation if the property is never accessed. Otherwise, just perform it upfront on construction.

    Note that properties are often understood to be “cheap” to evaluate – and while you’re making this lazy so that later accesses are cheap, this is still potentially going to be “heavy” enough on the first access to make a property inappropriate. Consider a ComputeXyz method instead.

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