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Home/ Questions/Q 8565111
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T17:21:00+00:00 2026-06-11T17:21:00+00:00

In the following code snippet p is a node in a binary search tree,

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In the following code snippet p is a node in a binary search tree, if the left child of p is not null I want to change p to point to its left child, but java is pass-by-value, when the function returns the structure of the tree remains unchanged.

void remove(BSTNode p)
{
    if(p.ch[0]==null)
        p=p.ch[0];
}

Actually I want to implement something like the following C++ code:

void remove(BSTNode* &p)
{
    if(p->ch[0]==NULL)
        p=p->ch[0];
}

For other reasons I don’t want to use the following way to return p.ch[0] and set p after every call to remove.

BSTNode remove(BSTNode p)
{
    if(p.ch[0]==null)
        return p.ch[0];
}

How can it be done?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T17:21:01+00:00Added an answer on June 11, 2026 at 5:21 pm

    You can save a pointer to the nodes parent ant then change it using that reference

    void remove(BSTNode p)
    {
        if(p.ch[0]==null){
        p.parent.ch[0] = p.ch[0];
    }
    
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